NCAA: So, it’s hard to actually calculate the exact odds of a perfect bracket, but if every game were a coin flip, the odds would be about 1 in 9.2 quintillion.Linked at hot air.com
but I’ve been focused on trigonometry. Mr Big Food is all about probability lately—
Bishop Reverend Bayes, et al. We will discuss.
The probability of the dude having a perfect bracket after 48 games is 2^48 or 1 in 281,000,000,000,000.
The probability of having a completely perfect bracket under the same assumptions, and including the play in games, is 2^67 or 1 in 1.47e20. Or put another way, 1 in 147,000,000,000,000,000,000; one in 147 quintillion.
How are they getting 9.2??
How is it “hard to actually calculate the exact odds of a perfect bracket?” Each game is played by two teams. In this scenario, each has even odds. There are a total of 67 games played. Two-to-the-sixty-seventh-power: 2^67.
Figured out yesterday’s trigonometry problem, by the way.